index.js

// Iteration 1: Names and Input
/*1.1 Create a variable hacker1 with the driver's name.
1.2 Print "The driver's name is XXXX".
1.3 Create a variable hacker2 with the navigator's name.
1.4 Print "The navigator's name is YYYY".*/

const hacker1 = "Joan"
const hacker2 = "Lorena"

console.log(`The driver's name is ${hacker1}`)
console.log(`The navigator's name is ${hacker2}`)


// Iteration 2: Conditionals
/*2.1. Depending on which name is longer, print:
- The driver has the longest name, it has XX characters. or
- It seems that the navigator has the longest name, it has XX characters. or
- Wow, you both have equally long names, XX characters!.*/

if ( hacker1.length > hacker2.length){
    console.log(`The driver has the longest name, it has ${hacker1.length} characters`)
}
else if( hacker1.length < hacker2.length){
    console.log(`It seems that the navigator has the longest name, it has ${hacker2.length} characters`)
}
else{
    console.log( `Wow, you both have equally long names, ${hacker1.length} characters!`)
}


// Iteration 3: Loops

/*3.1 Print the characters of the driver's name, separated by space, and in capital letters, i.e., "J O H N".
3.2 Print all the characters of the navigator's name in reverse order, i.e., "nhoJ".
3.3 Depending on the lexicographic order of the strings, print
The driver's name goes first.
Yo, the navigator goes first, definitely.
What?! You both have the same name?*/

//3.1
for (let i=0; i<hacker1.length; i++){
   console.log(hacker1[i].toUpperCase())
}
//3.2
for (let j=hacker2.length; j>-1; j--){
    console.log(hacker2[j])
}
//3.3
const nameOrder= hacker1.localeCompare(hacker2);

    if (nameOrder===-1){
console.log(`The driver's name goes first.`)
    }
    else if (nameOrder===0){
console.log(`Yo, the navigator goes first, definitely.`)      
    }
    else {
console.log(`What?! You both have the same name?`)     
    }